Question

Determine the zeros of x^2 + 4x - 16 = -2x .

Answer 1

So first you make equation equal 0

x^2 + 6x - 16 = 0           Add 2x to both sides

and use the equation:  x = -b ± (sqrt((b^2 - 4(a)(c))))/2a and Ax^2 + Bx + C = 0

A = 1
B = 6
C = -16

x = -3 ± (sqrt((36 + 64)))/2

x = -3 ± (sqrt(100))/2

x = -3 ± 5

x = 2
-and-
x = -8

Answer 2

First add 2x to both sides to get x^2 +6x -16=0 This will factor to (x+8)(x-2)=0;. Set each factor equal to zero and solve. (x+8)=0 x= -8. (x-2)=0. x=2