Determine the zeros of x^2 + 4x - 16 = -2x .
2 answers:
So first you make equation equal 0 x^2 + 6x - 16 = 0 Add 2x to both sidesx = -b ± (sqrt((b^2 - 4(a)(c))))/2a and Ax^2 + Bx + C = 0 A = 1 B = 6 C = -16 x = -3 ± (sqrt((36 + 64)))/2 x = -3 ± (sqrt(100))/2 x = -3 ± 5 x = 2 -and- x = -8
First add 2x to both sides to get x^2 +6x -16=0
This will factor to (x+8)(x-2)=0;. Set each factor equal to zero and solve. (x+8)=0 x= -8. (x-2)=0. x=2
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