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lutik1710 [3]
3 years ago
6

Multiply (5a+7)(5a-7)

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0
=25a^2-49
Steps
1)Simplify:(5a)^2-7^2
2)evaluate:25a^2-49
vovikov84 [41]3 years ago
5 0

Answer:

25a^2-49

Step-by-step explanation:

1)use FOIL

F=first

O=out

I=inside

L=last

5a*5a+5a*-7+7*5a*7*-7

25a^2-35a+35a-49

25a^2-49

Hope this helps!

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L = 5 and w = 3

Perimeter = 2(l + w)
P = 2(5 + 3)
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Area = l*w
Area = 5*3
Area = 15 cm^2
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Example: 1,2,3 are you numbers cross out the one then the 3

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Maria is learning to play golf. She has been working particularly hard on driving. Before lessons, her drive average 240 yards.
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Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b
Elenna [48]

Answer:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Step-by-step explanation:

We want to verify the identity:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }

Collect LCM

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }

We simplify the RHS to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}

We rationalize to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}

We expand to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}

Factor negative one in the denominator:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}

Apply the Pythagoras Property to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}

Simplify to get:

\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}

Or

\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}

Divide both the numerator and denominator by sin x

\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}

This finally gives:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

8 0
2 years ago
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