Question

43. Write a system of equations that is equivalent to each of the systems of equations below

Answer 1

1.

The new system of equivalent equations are 4x + 6y = 8 and 12x + 3y = 1

To get an equivalent equation, we multiply the original equation by a constant and replace it with the new equation.

So, 2x + 3y = 4 (1)

12x + 3y = 1 (2)

We multiply equation (1) by 2

So, 2x + 3y = 4 (1) × 2

⇒4x + 6y = 8 (3)

Replacing (1) by (3), we have

4x + 6y = 8 (3)

12x + 3y = 1 (2)

So, the new system of equivalent equations are 4x + 6y = 8 and 12x + 3y = 1.

2.

The new system of equivalent equations are 3x - 21y = 24 and 5x + 4y = 20

To get an equivalent equation, we multiply the original equation by a constant and replace it with the new equation.

So,

x - 7y = 8  (1)

5x + 4y = 20 (2)

We multiply equation (1) by 3, we have

So, x - 7y = 8 (1) × 3

⇒3x - 21y = 24 (3)

Replacing (1) by (3), we have

3x - 21y = 24 (3)

5x + 4y = 20 (2)

So, the new system of equivalent equations are 3x - 21y = 24 and 5x + 4y = 20.

Learn more about equivalent equations here:

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