Katalina is solving algebraic expressions for her math homework. She solves the problem 7y -12, when y = 3. Katalina says that t
1 answer:
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Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x =
x - 3 = 0; x = 3
the solutions are
Both values are real numbers, therefore correct option is b
Answer:
See explanation below
Step-by-step explanation:
According to the solubility curve attached, let's analyze each sentence to see which one is correct:
<u>"Solubility of NaCl is least affected by temperature"</u>
True. as you can see in the curve, solubility of NaCl remains almost constant at any value of temperature, so in this case, it does not matter the temperature, the NaCl solubility will be the same.
<u>"completely dissolve 60 g of KBr in 100 g of water at 20 °C"</u>
True. As you can see in the graph, solubility of KBr begins at 60 g, so in 20 °C we have something dissolved there. Actually you have like 70 g dissolved there, so, this is true.
<u>"The solubility of KNO3 is the least affected by changes in temperature"</u>
False. The curve for KNO3 is exponencial, so, changes in temperature do actually affect the solubility.
<u>"100 g of KBr will dissolve completely in 100 g of water at 75 °C"</u>
False. According to the curve, 100 g dissolve when we reach more than 100 °C. At 75 °C only about 85 g of KBr is dissolved.
<u>"if you mix 120 g of NaClO3 in 100 g of water at 10 °C, approximately 30 g will not dissolve"</u>
True. In the graph we can clearly see that at 10 °C only about 90 g is being dissolved so, the rest of the mass is still there as mass.
