Answer:
El área de un rectángulo de largo L y ancho A es: L*A.
El área de un triangulo de alto H y base B es: H*B/2.
Ahora veamos las tres figuras:
Rectángulo amarillo:
Largo = 40m
Ancho = 45m
Área = 40m*45m = 1800 m^2
Rectángulo blanco:
Largo = 40m
Ancho = 35m
Área = 40m*35m = 1400m^2
Triangulo azul:
Base = 35m
Alto = 50m
Área = 35m*50m/2 = 875m^2
Area total = 1800 m^2 + 1400m^2 + 875m^2 = 4075m^2
Answer:
The first option
Step-by-step explanation:
Adjacent angles are just two angles next to each other
<span>f(-10)=12, x = -10, y = 12
f(16)=-1, x = 16, y = -1.
so, we have two points, let's check with that,
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![\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)} y-12=-\cfrac{1}{2}[x-(-10)] \\\\\\ y-12=-\cfrac{1}{2}(x+10)\implies y-12=-\cfrac{1}{2}x-5\implies y=-\cfrac{1}{2}x+7](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7D%5Bx-%28-10%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-12%3D-%5Ccfrac%7B1%7D%7B2%7D%28x%2B10%29%5Cimplies%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7Dx-5%5Cimplies%20y%3D-%5Ccfrac%7B1%7D%7B2%7Dx%2B7)
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1. 2² times 7¹
2. 2² times 3²
3. 29 is a prime number already
4. 2¹ times 5¹ times 7¹
5. 5¹ times 11¹
6. 3⁴
7. 2³ times 3¹ times 7¹
8. 3² times 11¹
9. 3¹ times 5²
10. 2⁶
Answer:
The area he can cover with that weapon is 1,256 miles².
Step-by-step explanation:
Assuming that the Jedi won't move and that he can shoot in every direction, he'd be shooting at a circle with a radius of 20 miles. Therefore the are that he can cover with that weapon is the area of the circle, which is shown below:
area = pi*r²
area = 3.14*(20)²
area = 3.14*400
area = 1,256 miles²
The area he can cover with that weapon is 1,256 miles².
