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Tresset [83]
3 years ago
13

What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = \frac{\alpha }{360} X \pi r^2

On substituting the value, we get:

A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2

Therefore, the area of the sector is 86.81π mm²

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Jellybeans are stored in a container. The jellybeans (on their own) weigh a net mass of 60g and the container weighs a net mass
boyakko [2]

As per the mentioned details, the gross mass of the container is 65 grams.

The gross mass of the container is defined as the total mass of the package. It includes the mass of constituents and the mass of containing body. So, here the sum of mentioned masses will be the gross mass of the container.

Gross mass of the container = 60 + 5

Performing addition on Right Hand Side of the equation to find the gross mass of the container

Gross mass of the container = 65 grams

Thus, the gross mass of the container is 65 grams.

Learn more about gross mass -

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3 0
1 year ago
Helloppp i need hwlp with this plllss
Rasek [7]
the answer is b because x is greater than or equal to 0
3 0
2 years ago
Which model represents the product of One-fifth × One-sixth? A fraction bar divided into 30 parts. 5 are shaded. A fraction bar
Lera25 [3.4K]

Answer: The third choice

Step-by-step explanation:

\frac{1}{5}* \frac{1}{6} =\frac{1*1}{5*6} \\\\\frac{1*1}{5*6}\frac{1}{30}

Hope it helps <3

3 0
3 years ago
I do not know how to solve this problem or know what to do with the exponents
horsena [70]
K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
(ab)^c=(a^c)(b^c)
and
x^{-m}= \frac{1}{x^m}
and
x^ \frac{m}{n}= \sqrt[n]{x^m}
and
( \frac{x}{y} )^m= \frac{x^m}{y^m}
and
(x^m)^n=x^{mn}
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)


so
( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}=
( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}=
( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )=
( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )=
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )=
(\frac{25}{49} )( \frac{y^8}{x^3}=
\frac{25y^8}{49x^3}
4 0
3 years ago
Writing Linear Equations. <br> help is needed
dlinn [17]

Answer:

C=4m+30

4 0
3 years ago
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