6a-3b^2-a+b-4+7a^2
goup like terms
7a^2-3b^2+6a-a+b-4
7a^2-3b^+5a-4
Answer:
-51t+45
Step-by-step explanation:
-6(3t-6)-3(11t-3)
-18t+36-33t+9
-51t+45
Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle:
bh =
⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 =
⋅20 = 10
Our area is 10 square units.
Hope that helps :)
When (-5, 2) is reflected across the y-axis then it becomes (5, 2). When (-5, 2) is reflected across the x-axis, it becomes (-5, -2)
I hope this helps out!