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exis [7]
3 years ago
9

Cards from an ordinary deck of 52 playing cards are turned face up one at a time. If the 1st card is an ace, or the 2nd a two, o

r the 3rd a three, or . . . , or the 13th a king, or the 14th an ace, or the 15th a two, and so on, we say that a match occurs. Compute the expected number of matches that occur.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

Expected number of matches that occur = 4 matches

Step-by-step explanation:

First of all, let X_i be the event that when we turn over card i if it matches the required cards face.

Thus, for example X_1 is the event that turning over one card results in an ace while X_2 is the event that turning over second card reveals a deuce.

The number of matched cards "N" is given by the sum of this indicator random variable as shown in the attached file;

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12x=3x+63 addition
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x=7 division

the value of x that makes the equation true is 7.

8 0
3 years ago
What are the slopes of the two lines? <br> green has two yellow dots.
IrinaVladis [17]

Answer:

-7(1/7) = -1

Step-by-step explanation:

4 0
3 years ago
Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours. Machines A and B beg
ycow [4]

Answer:

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Step-by-step explanation:

Consider the provided information.

Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours.

Thus, in 1 hr machine A's work is 1/a and machine B's work is 1/b.

We need to find whether the Machine A's rate the same as that of Machine B?

Statement 1: Machines A and B finish the order at exactly 4:48 p.m.

Total time, A and B worked = 4:48 = 4+\frac{48}{60} hrs = 4+\frac{4}{5} hrs= \frac{24}{5} hours

Thus, \frac{1}{a}+\frac{1}{b} = \frac{5}{24}

Let say Machine A's rate the same as that of Machine B

\frac{1}{a}+\frac{1}{a} = \frac{5}{24}\\\\\frac{2}{a} = \frac{5}{24}\\\\a = \frac{48}{5}

It is given that a and b are even integers, but \frac{48}{5} is not an even integer.

Hence, Machine A's rate is not same as that of Machine B.

Therefore, statement (1) ALONE is sufficient.

Statement 2: (a + b)^2 = 400

(a+b)^2 = 400\\a+b=20

There are many possible case in which a and b are even integer and there sum is 20.

If a = b = 10 (both even), then Machine A's rate is same as that of Machine B.

if a = 6 and b = 14 (both even), then Machine A's rate is not same as that of Machine B.

Therefore, No unique answer with statement 2.

Hence, statement 2 alone is not sufficient.

6 0
3 years ago
Solve the system of linear equations by graphing. x−y=7 0.5x+y=5
tatiyna

Answer:

Hope this helps!

Step-by-step explanation:


8 0
3 years ago
9y + 9 - 3y + 7 = 2y + 4<br><br> y = Answer
DENIUS [597]

Answer:

y = -3

Step-by-step explanation:

9y + 9 - 3y + 7 = 2y + 4

Collect like terms;

6y + 16 = 2y + 4

Subtract 2y from both sides;

4y + 16 = 4

Subtract 16 from both sides;

4y = -12

Divide both sides by 4;

y = -3

7 0
3 years ago
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