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3 years ago

What is the coefficient of y in the expression 2 ⋅ 4 + 3y?

2 answers:

5 0

A coefficient is the number that is multiplied by the variable (the letter).
so the coefficient in ur expression is 3.

the 2 and the 4 are constants...because they are numbers with no variables

svetoff [14.1K]3 years ago

3 0

3 Is your coefficient because what ever in front of your variable is your coefficient
. :)

You might be interested in

Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya would have bought 2

defon

Answer:

Option C

The student's conclusion is correct because the solution to the system of equations $3x+2y=27$ and $2x+y=16$ is $(5,6)$

Step-by-step explanation:

Let

x------> the cost of each burger

y-----> the cost of each sandwich

we know that

$3x+2y=27$ -----> equation A

$2x+y=(27-11)$

$2x+y=16$ ----> equation B

Solve the system of equations

Multiply the equation B by $-2$

$-2(2x+y)=-2*16$ -----> $-4x-2y=-32$ ------> equation C

Adds equation A and equation C

$3x+2y=27 \\-4x-2y=-32\\ ----------\\ 3x-4x=27-32\\ -x=-5\\x=5$

Substitute the value of x in the equation B

$2(5)+y=16$

$10+y=16$

$y=6$

The solution of the system of equations is the point $(5,6)$

The price of each burger is $\$5$

The price of each sandwich is $\$6$

6 0

2 years ago

Read 2 more answers

Hey, mind helping me out?

maxonik [38]

Answer:

$h \leq 16$

Step-by-step explanation:

h + 4 ≤ 20

Subtract 4 from both sides.

h ≤ 20 − 4

Subtract 4 from 20 to get 16.

$h \leq 16$

Hope it helps and have a great day! =D

~sunshine~

8 0

1 year ago

Read 2 more answers

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

PLEASE HELP!! (50 POINTS)

Marrrta [24]

Answer:

Since pair of opposite sides are parallel and adjacent sides meets at right angles, the quadrilateral COAT is a rectangle.

Step-by-step explanation:

The vertices of the given quadrilateral is $C(2,0),O(7,0),A(7,2),T(2,2)$

It is sufficient to show that pair of opposite sides are parallel and adjacent sides are perpendicular.

The slope of each side can be found using the formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of CO,

$M_{CO}=\frac{0-0}{7-2}=\frac{0}{5} =0$

A line with a zero slope is a horizontal line.

The slope of OA,

$M_{OA}=\frac{2-0}{7-7} =\frac{2}{0}$

This slope is undefined.

A line with an undefined slope is a vertical line.

This shows that,the side CO and OA of the quadrilateral meets at right angle.

The slope of AT,

$M_{AT}=\frac{2-2}{7-0}=\frac{0}{5}=0$

This is also a horizontal line.

The slope of TC,

$M_{TC}=\frac{2-0}{2-2} =\frac{2}{0}$

This also a vertical line.

This implies that, side TC and side AT meets at Tat right angles and TC is parallel to OA.

Also AT is parallel to TO.

This shows that COAT is a rectangle.

8 0

3 years ago

ANSWER ASAP GIVING BRAILIEST AND STUFF!

natita [175]

Answer:

24s^2, 54s^2, 96s^2

Step-by-step explanation:

Let s represent the initial side length of the cube. Then the area of each face of the cube is A = 6s^2 (recalling that the area of a square of side length s is s^2).

a) Now suppose we double the side length. The total area of the 6 faces of the cube will now be A = 6(2s)^2, or 24s^2 (a 24 times larger surface area),

b) tripled: A = 6(3s)^2 = 54x^2

c) quadrupled? A = 6(4s)^2 = 96s^2

6 0

2 years ago