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Alenkasestr [34]
4 years ago
8

A survey of middle school students asked: What is your favorite winter sport? The results are summarized below:Favorite Winter S

portpolarbear Grade MB Snowboarding Skiing Ice Skating TOTAL6th 68 41 46 1557th 84 56 70 2108th 59 74 47 180TOTAL 211 171 163 545Using these 545 students as the sample space, a student from this study is randomly selected. a) What is the probability of selecting a student whose favorite sport is skiing?b) What is the probability of selecting a 6th grade student?c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?

Mathematics
1 answer:
Annette [7]4 years ago
7 0

Answer:

a) 31.38%

b) 28.44%

c) 33.33%

d) 73.46%

e) 53.89%

Step-by-step explanation:

<h3>(See picture attached for sub-totals) </h3>

a) What is the probability of selecting a student whose favorite sport is skiing?

P = 171/545 = 0.3138 = 31.38%

b) What is the probability of selecting a 6th grade student?

P = 155/545 = 0.2844 = 28.44%

c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?

P = 70/210 = 0.3333 = 33.33%

d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?

P = 155/211 = 0.7346 = 73.46%

e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?

P = 180/(171+163) = 180/334 = 0.5389 = 53.89%

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PLEASEEE HELPPPP IM BEGGIN U
Anna71 [15]

Answer:

  a) positive real zeros: 2 or 0; negative real zeros: 2 or 0; complex zeros: 0, 2, or 4. (rule of signs)

  b) ∪-shaped, as for an even-degree polynomial with positive leading coefficient. See attached.

  c, d) See attached

Step-by-step explanation:

Descarte's rule of signs gives bounds on the number of positive and negative real roots. The numbers it gives may be reduced by multiples of 2, as complex roots will come in conjugate pairs. The total number of roots of all kinds will match the degree of the polynomial.

Synthetic division is essentially polynomial long division with some modifications:

  • the variables are omitted ("place value" is used instead)
  • the constant in the divisor is <em>negated</em> so its product with the partial quotient can be <em>added</em> to obtain the new dividend
  • the divisor binomial is assumed to have a leading coefficient of 1.

__

<h3>a) </h3>

The signs of the terms of the given polynomial are + - - - +. There are two sign changes, so 2 possible positive real roots.

When the signs of the odd-degree terms are changed, the signs become + + - + +. There are still two sign changes, so 2 possible negative real roots.

Either or both of these numbers can be reduced by 2 if the roots include a conjugate pair. That is, there may also be 0 possible positive real roots, and 0 possible negative real roots.

The number of non-real (complex) zeros may be any multiple of 2 up to the degree of the polynomial. The may be 0, 2, or 4 possible non-real zeros.

__

<h3>b)</h3>

The graph is the first attachment. It shows 4 real zeros: x = -4, -2, 1, 6.

Since the polynomial is of even degree (4) and has a positive leading coefficient (+1), we expect the general shape to be ∪-shaped. It is.

__

<h3>c)</h3>

The second attachment shows synthetic division using x = -4. (The binomial divisor is (x+4).) The remainder (lower right value in the tableau) is the value of y when x=-4. The third attachment shows synthetic division using the value x=3. (y is -210 when x=3.)

Maybe this is the table you want:

  \begin{array}{|c|c|c|}\cline{1-3}x&-4&3\\\cline{1-3}y&0&-210\\\cline{1-3}\end{array}

__

<h3>d)</h3>

The second attachment shows synthetic division by the factor (x+4).

_____

<em>Additional comment</em>

The synthetic division attachments show instructions for carrying out the synthetic division and interpreting the results. As we said above, "the entry on the left" is the opposite of the constant in the binomial divisor. It is the actual value of x you want to use to evaluate the function.

The equations shown are merely for the purpose of indicating the operations that are used. An actual synthetic division tableau is simply a 3-row table of numbers, with the bottom row being the quotient coefficients and remainder.

6 0
2 years ago
PLEASE HELP <br><br> THERE ARE MANY QUESTIONS LIKE THIS ON MY PAGE SO U CAN JUST KEEP GETTING POINTS
Nastasia [14]

Answer: 1

Step-by-step explanation:

first, i multiplied it all out.

1.5^2/1.5^2

then, i simply divided it all.

1

8 0
3 years ago
at the market, a housewife bought 2 kilograms of eddoes at $5 per kilogram and 5 kilograms of chicken at $10 per kilogram. she p
madam [21]

Answer:

The total for the housewife's purchase should be 60 dollars. So it should be the vender who owes her money. The vender owes her 15 dollars.

Step-by-step explanation:

$5 = 1kg (eddoes) meaning a total of 2kg eddos =$10

$10 = 1kg (chicken) meaning a total of 5kg chicken = $50

When added together, it'd be 60 dollars.

(I'm not sure if you maybe forgot a part of the question or only had this part)

4 0
3 years ago
What do i write in all of these boxes
Degger [83]

Answer:

40 30 76 24 56

Step-by-step explanation:

This is a rashio so youll need to find out the number of nuts to raisans.

6 0
3 years ago
Find the six trig function values of the angle 240*Show all work, do not use calculator
-BARSIC- [3]

Solution:

Given:

240^0

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

sin240^0=sin(180+60)

Using the trigonometric identity;

sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny

Hence,

\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\  \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\  \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

cos240^0=cos(180+60)

Using the trigonometric identity;

cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny

Hence,

\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\  \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\  \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

tan240^0=tan(180+60)

Using the trigonometric identity;

tan(180+x)=tan\text{ }x

Hence,

\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\  \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}

To get cosec 240 degrees:

\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\  \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\  \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\  \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}

To get sec 240 degrees:

\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\  \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\  \\ Thus, \\ sec240^0=-2 \end{gathered}

To get cot 240 degrees:

\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\  \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\  \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\  \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}

5 0
1 year ago
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