Answer:
y²-3y+2=0
=> y²-(2+1)y +2=0
=> y²-2y-y+2=0
=> y(y-2)-1(y-2)=0
=> (y-2)(y-1)=0
=> y = 2 or y= 1
this is what I found:
9
Step-by-step explanation:
mark brainliest please :)
asasassasas
