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anzhelika [568]
2 years ago
14

Which table shows the same relationship as y = -x^2 + 3x?

Mathematics
1 answer:
kkurt [141]2 years ago
8 0

Answer:

H

Step-by-step explanation:

given y = -x² + 3x.

let f(x) be y.

f(-2) = -(-2)² + 3(-2) = -10

f(-1) = -(-1)² + 3(-1) = -4

f(0) = -(0)² + 3(0) = 0

f(1) = -(1)² + 3(1) = 2

f(2) = -(2)² + 3(2) = 2

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-300 =5x-(-8x+3) step by step
cupoosta [38]

Answer:

x=  −297 /13

Step-by-step explanation:

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3 years ago
The sum of two numbers is 61 and the difference is 17 . what are the numbers?
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The two numbers are 39 and 22
6 0
3 years ago
Given the function f(x) = -5|x + 11 + 3, for what values of x is f(x) = -12?
katen-ka-za [31]

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Step-by-step explanation:

6 0
3 years ago
What is the range of the function
alexandr1967 [171]

Answer: Choice B

Range = {-3, 1, 5}

============================================

Explanation:

The domain is the set of all possible input x values. The range is the set of all possible y outputs.

Plug in each x value from the domain, one at a time, to get its corresponding range y value.

--------------------

Start with x = -3

f(x) = 2x+3

f(-3) = 2(-3)+3

f(-3) = -6+3

f(-3) = -3

So -3 is in the range.

--------------------

Move onto x = -1

f(x) = 2x+3

f(-1) = 2(-1)+3

f(-1) = -2+3

f(-1) = 1

1 is also in the range

--------------------

Finally plug in x = 1

f(x) = 2x+3

f(1) = 2(1)+3

f(1) = 2+3

f(1) = 5

The value 5 is the final value in the range.

--------------------

All of those values form the set {-3, 1, 5} which is the complete range.

7 0
3 years ago
What is y=3x^2-2 in vertex form
Nata [24]
\bf \qquad \qquad \textit{parabola vertex form}
\\\\\\
y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
y=3x^2-2\iff y = 3(x-0)^2-2
3 0
3 years ago
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