Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
The answer for your question is a
I believe the answer is x = 1
9514 1404 393
Answer:
Step-by-step explanation:
The acute angles in a right triangle are complementary:
2x° +(x -6)° = 90°
3x = 96 . . . . . . . . . divide by °, add 6
x = 32 . . . . . . . . . divide by 3
(x-6)° = (32 -6)° = 26°
2x° = 2(32)° = 64°
The acute angles have measures 26° and 64°.