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Wittaler [7]
3 years ago
5

The difference between five times a number and twice that number

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0
<span>The difference between five times a number and twice that number = 15</span>
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How do you find the are of the diameter
GalinKa [24]
I think you mean circumference, which is equal to = 2πr
6 0
3 years ago
Question 12 (1 point) Given P(A) 0.34, P(A and B) 0.27, P(A or B) 0.44, what is P(B)? Answer in decimal form. Round to 2 decimal
Tema [17]

Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

P(A) = 0.34,    P(A ∩ B) = 0.27   and   P(A ∪ B) = 0.44.

We are to find the probability of event B, P(B) = ?

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.

Thus, the required probability of event B is P(B) = 0.37.

6 0
3 years ago
Complete the statement to explain why 8,000 divided by 800 = 10
ddd [48]
Because when you multiply by 10, it adds a zero to the end of the number, like       12*10 = 120, so vise versa for dividing
7 0
3 years ago
Read 2 more answers
I need help on this I am just going to use the picture
Radda [10]

Answer:

D

Step-by-step explanation:

let y = f(x), that is

y = \frac{2x-3}{5}

Rearrange making x the subject

Multiply both sides by 5

5y = 2x - 3 ( add 3 to both sides )

5y + 3 = 2x (divide both sides by 2 ) , then

x = \frac{5y+3}{2}

Change y back into term of x, hence

f^{-1}(x) = \frac{5x+3}{2} → D

4 0
3 years ago
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Find the missing angle.
Sphinxa [80]

Answer:

m\angle XYV=135^{\circ}

Step-by-step explanation:

Notice that m\angle XYV=m\angle XYW+m\angle VYW.

The diagram already marks m\angle VYW=80^{\circ}, so we just need to find m\angle XYW.

\angle TYU and \angle XYW are vertical angles, which means they are equal in measure.

Therefore,

m\angle TYU=m\angle XYW=6x+7

Since there are 180^{\circ} on each side of a line, we have the following equation:

m\angle XYW+m\angle VYW+m\angle UYV=180^{\circ},\\6x+7+13+4x+80=180,\\10x+20=100,\\10x=80,\\x=8.

Plugging in x=8, we have:

m\angle XYW=6(8)+7=55^{\circ}.

Therefore,

m\angle XYV=55^{\circ}+80^{\circ},\\m\angle XYV=\fbox{$135^{\circ}$}.

5 0
3 years ago
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