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4 years ago

6

Use the drop-down menus to complete the statements.

1 answer:

dlinn [17]4 years ago

5 0

Answer:the xylem transports water and nutrients throughout the plant

the pholem transports food throughout the plant.

Explanation:mark brainliest cuz like i gave u the answer lol

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A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve

Helen [10]

Answer:

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

Explanation:

The differential equation is given as:

$\frac{dC}{dt} = r- kC$

$\frac{dC}{r- kC} = dt$

Taking integral of both sides; we have:

$\int\limits \frac{dC}{r- kC} = \int\limits dt$

$-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD$

$r-kC=e^{-kt-kD}$

$r-kC=e^{-kt}e^{-kD}$

$r-kC=Ae^{-kt}$

$kC=r-Ae^{-kt}$

$C=\frac{r}{k}-\frac{A}{k}e^{-kt}$

$C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}$ ------- equation (1)

If C(0)= $C_o$ ; we have:

C(0)= $\frac{r}{k}-\frac{A}{k}e^0$ (where; A is an integration constant)

$C_o = \frac{r}{k}- \frac{A}{k}$

$C_o=\frac{r-A}{k}$

$kC_o=r-A$

$A=r-kC_o$

Substituting $A=r-kC_o$ into equation (1); we have;

$C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}$

3 0

4 years ago

what if your friend joked that a cell is like his little brother's bathtub with tub toys floating in it

Natasha2012 [34]

Answer:

no

Explanation:

a cell is something that either stays inside of something or is a individual floating object and it does not compare to bigger sized materials

5 0

4 years ago

The absorbance of a cationic iron(II) sample solution was measured in a spectrophotometer, but the instrument returned an error

JulijaS [17]

Answer:

$1.35\times 10^{-4} M$ was the concentration of the original solution.

Explanation:

$M_1V_1=M_2V_2$ (Dilution)

where,

$M_1\text{ and }V_1$ are molarity and volume of non diluted sample.

$M_2\text{ and }V_2$ are molarity and volume of diluted sample.

$M_1=?$

$V_1=100.0 \mu L=0.1 mL$

(1μL=0.001 mL)

$M_2=6.41\times 10^{-6} M$

$V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL$

Substituting all values :

$M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL$

$M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M$

$1.35\times 10^{-4} M$ was the concentration of the original solution.

5 0

3 years ago

Choose all the right answers.

gayaneshka [121]

I think the answer is

Reduce friction

:)

8 0

3 years ago

Please Helppppp:(((((

kozerog [31]

Answer:

do we add???

Explanation:

6 0

3 years ago

Read 2 more answers