What is the pH of a pure 0.5L batter acid from the PhET simulation?

True or false <br> The sodium atom becomes a sodium ion with a charge of +1

ddd [48]

Answer:

True

Explanation:

The sodium atom does become a sodium ion with a charge of +1.

6 0

1 year ago

What does sodium react with

Pani-rosa [81]

Sodium reacts with water to form a colorless solution of sodium hydroxide and hydrogen gas.

5 0

2 years ago

Which substance has Hf defined as 0 kJ/mol? H2O (s) Ne (l) O2 (g) CO2 (g)

vlabodo [156]

Answer:

O₂ (g).

Explanation:

All elements that found in nature has heat of formation (Hf) equal 0 J/mol.

So, the substance that has heat of formation (Hf) equal 0 J/mol is O₂ (g).

H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).

Although, Ne (g) is found in nature and has no Hf, the liquification to form Ne (l) has heat of formation (Hf).

CO₂ (g) is formed from the reaction between carbon and oxygen and so has heat of formation (Hf).

8 0

2 years ago

Read 2 more answers

Infrared (IR) spectroscopy is used to identify functional groups within a molecule. Click on the peak that corresponds to the st

Sergio [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct place to click on any of the double peak showing between 2500 and 3000 $cm^{-1}$ on the uploaded question

Explanation:

The group which is being highlighted is an Aldehyde functional group denoted by this structure ( $=C-H$ )

This groups stretch on the infrared spectrometer gives two medium intensities peaks

Its stretch comes at 2820 - 2850 $cm^{-1}$ peak 1

and at 2720 - 2750 $cm^{-1}$ peak 2

So the correct click would be on any of the two peaks between 2500 - 3000 $cm^{-1}$ region

7 0

2 years ago

A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by

Alla [95]

Answer: 1. The empirical formula is $PNF_2$

2. The molecular formula is $PNF_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P = $\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles$

Moles of N = $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles$

Moles of F = $\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = $\frac{1.20}{1.20}=1$

For N = $\frac{1.20}{1.20}=1$

For F = $\frac{2.41}{1.20}=2$

The ratio of P: N: F= 1: 1: 2

Hence the empirical formula is $PNF_2$

The empirical weight of $PNF_2$ = 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1$

The molecular formula will be= $1\times PNF_2=PNF_2$

3 0

2 years ago