The answer is 79.9 g.
Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g
Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
Answer:
Explanation:
1. Atomic mass of T
To get the atomic mass of T, you calculate the weighted average of the atomic masses of the isotopes.
That is, you multiply the atomic mass of each isotope by a number representing its relative importance (e.g.., its percent of the total).
2. Identity of T
Lithium has an atomic mass of 6.64 u.
Element T is lithium.
Answer:
<em>D. A combustion reaction</em>
Explanation:
CH2OHCH2OH is a
general example of a polyhydroxyl alcohol. A polyhydroxyl alchol is one in which
there are two hydroxyl groups present in the substance. The –OH group attached
to both the carbon atoms.
Explanation:
When an acid reacts with a base then it results in the formation of salt and water.
is an acid and 
is a base thus, when we dissolve ammonium hydroxide in nitric acid then it results in the formation of ammonium nitrate and water.
The reaction is as follows.
Hence, there will be formation of ammonium nitrate 
salt.
