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spayn [35]
3 years ago
12

The activation energy of a reaction going on its own is 20 kj. If the reaction was treated with a catalyst, which would most lik

ely represent the amount of energy needed to start a reaction?
15 kj
20 kj
25 kj
30kj
Physics
2 answers:
storchak [24]3 years ago
7 0

Answer:

15 kJ

Explanation:

We need to know the following;

what is activation energy?

  • Activation energy is the minimum energy required by reactants for a chemical reaction to take place.

What are catalysts?

  • Catalysts are molecules or substances that speed up the rate of a chemical reaction.
  • In other words, catalysts increase the speed at which products are formed from reactants.

How do catalysts speed up reactions?

  • Catalysts speed the rate of chemical reactions by lowering the activation energy of the reactants.
  • When activation energy is lowered, reactants require less energy for the reaction to occur which easily achieved making the reaction proceed faster.
  • Therefore, in presence of a catalyst, the new activation energy should be lower than the initial value of activation energy.
Arte-miy333 [17]3 years ago
5 0

Answer:

A 15kj

Explanation:

just did the assignment

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A grating has 460 rulings/mm. What is the longest wavelength for which there is a 6.0th-order diffraction line
mestny [16]

Answer:

λ = 3.62 x 10⁻⁷ m = 362 nm

Explanation:

The grating equation gives the relationship between the wavelength, the diffraction line order and the diffraction angle. The grating equation is written as follows:

mλ = d Sinθ

where,

m = order of diffraction = 6

λ = longest wavelength = ?

d = 1/(460 rulings/mm)(1000 mm /1 m) = 2.17 x 10⁻⁶ m/ruling

θ = Diffraction angle = 90° (for longest wavelength)

(6)λ = (2.17 x 10⁻⁶ m/ruling) Sin 90°

λ = (2.17 x 10⁻⁶ m/rulings)/6

<u>λ = 3.62 x 10⁻⁷ m = 362 nm</u>

3 0
4 years ago
A hummingbird 3.4m above the ground flies 1.2 m along a straight line path. Upon spotting a flower below, the hummingbird drops
Anit [1.1K]

A = horizontal displacement of the humming bird = 1.2 m

B = vertical displacement of the humming bird = 1.4 m

C = net displacement of the humming bird from initial to final position = ?

In the triangle drawn , Using Pythagorean theorem

C = √(A² + B²)

inserting the values

C = √(1.2² + 1.4²)

C = √(1.44 + 1.96)

C = √(3.4)

C = 1.4 m

Hence the net displacement of hummingbird comes out to be 1.4 m

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3 years ago
Read 2 more answers
A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17
Korolek [52]

<span>Given:

Mass of cart: 15kg</span>

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

 

So, the solution would be like this for this specific problem:

 

<span><span>1)    </span>W(by applied force) = F(applied) x s x cosθ <span>
=>W(a) = 12 x 14 x cos17* = 160.66 J </span></span>
<span><span>
2)    </span>By F(net) = F(applied) - F(friction) <span>
=>As v = constant => a = 0 => F(net) = 0 
=>F(applied) = F(friction) 
<span>=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s 
=>W(f) = -12 x 14 x cos17* = -160.56 J </span></span></span>
<span><span>
3)    </span>0, as the displacement is perpendicular to Force </span>
<span><span>
4)    </span>0, as the displacement is perpendicular to Force</span>  
<span>
To add, the force that is applied<span> to an object by a person or another object is called the applied force.</span></span>
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igomit [66]
<span>An automobile with a mass of 1450 kg is parked on a moving flatbed railcar; the flatbed is 1.5 m above the ground. The railcar has a mass of 38,500 kg and is moving to the right at a constant speed of 8.7 m/s on a frictionless rail...
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Vera_Pavlovna [14]

Answer:

Correct answer is A.

The higher the enzyme, the higher the Vmax

Explanation:

Although, in the absence of enzyme, the rate of a reaction(Vmax) increase linearly with substrate concentration. The reaction rate is given as dp/dt.

The rate of a reaction involving enzyme also increases.

At low enzyme concentrations or high substrate concentrations, all of the available enzyme active sites could be occupied with substrates. Therefore, increasing the substrate concentration further will not change the rate of diffusion. In other words, there is some maximum reaction rate (Vmax) when all enzyme active sites are occupied. The reaction rate will increase with increasing substrate concentration, but must asymptotically approach the saturation rate, Vmax. Vmax is directly proportional to the total enzyme concentration, E

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