For the first one I got :
V = 165/8
V = B*h
(B)11/2 * (h)15/4
= 165/8
Pls correct me if im wrong!! :)
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
Function:(7,-4), (0,9), (2,-2)
(-6,5),(-5,6), (8,2)
(2,3),(6,-5),(-1,3)
Not a function:(0,3),(0,7),(4,0)
(1,9),(-3,-2),(1,-4)
Answer:
x = - 4
Step-by-step explanation:
5x + 55 = 35 ( subtract 55 from both sides )
5x = - 20 ( divide both sides by 5 )
x = - 4
<span>The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate must she return if the total travel time is three hours and forty minutes?
1st leg DATA:
distance = 90 mi ; rate = 45 mph ; time = d/r = 2 hrs.
</span><span>2nd leg DATA:
distance = 90 mi ; time = [3 2/3 - 2] = 1 2/3 hrs; rate = 90/(5/3) = 54 mph
Ans: 54 mph</span>
