The answer is c. because when you distribute it out, it equals the top equation
Simple...
you have: 27-9x+15
Add any terms that are the same-->>
-9x+42
Factor-->>>
-3(3x-14)
Thus, your answer.
Answer:
The one you are on, f(x+2)+4
Step-by-step explanation:
First, we can see by the 0 point that it is just moved up by 4 and not left or right any, so we want to see how it has changed without the +4.
in g(x) the x changes by two, 0 to 2, and the y changes by one, 4 to 5.
Hopefully you can tell what the function being manipulated is. It is x^3 so if we write that instead of f(x) in the answers the first one for instance would be (x/3)^3-4. (let me know if that doesn't make sense)
SInce we already know it's being moved up by 4, we know it's one of those with +4 at the end. It's easy enough to guess and check, but the process to find the answer is pretty easy. We also know that at 2, the change is 1. So without the +4 at the end, what would let us change 8 to 1? dividing it by 8, which is also 2^3. so that means (2/2)^3. So the answer is we want f(x/2) witht he +4 at the end.
Hopefully that made sense, I'd be happy to explain further if you need though
Answer:
length ofGH
Step-by-step explanation:
distance=√{(-2+9)²+(-6+4)²}=√{7²+(-2)²}=√53=7.28=7.3 units
Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.