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BlackZzzverrR [31]
3 years ago
13

WILL GIVE BRAINLIEST, THANK YOU, AND RATING!!!

Mathematics
1 answer:
frozen [14]3 years ago
5 0
64-128-256
each step double previous number
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5(x + 6) - 2r = 3(x + 10)<br> Solve for X
Svetllana [295]

5x+30-2r=3x+30

5x-3x=30+2r

2x=30+2r

x=(30+2r)÷2

7 0
3 years ago
PLEASE HELP THANK YOU!!!
Paul [167]

Answer:

Only C is a function

Step-by-step explanation:

To test whether a graph is a function you use the vertical line test.

If you can place a vertical line anywhere on the plane (in the domain of the "function" to be tested) and it intersects the curve at more than one point, the curve is not a function.

We see with A, wherever we put the vertical line it intersects twice.

With B, it intersects infinitely many times.

C is a function because wherever we put the vertical line, it only intersects once.

D is a function because it intersects twice providing we do not put it on the "tip" of the parabola.

The mathematical reasoning behind this is that a function must be well-defined, that is it must send every x-value to one specific y-value. There can be no confusion about where the function's input is going. If you look at graph B and I ask you what is f(3)? Is it 1? 2? 3? ... Who knows, it's not well-defined and so it's not a function. However if I ask you about C, whichever input value for x I give you, you can tell me to which y-value it gets mapped/sent to.

7 0
3 years ago
Second derivative of sec^2(πx)
Digiron [165]
 <span>let y = sec^2 ( pi x ) 

y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi 

y' = 2pi sec^2 ( pi x ) tan ( pi x ) 

y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x ) 

y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
6 0
3 years ago
Read 2 more answers
6 fl oz= how many cups
natima [27]
1 oz = 0.125 cups so 6 oz = 0.75 cups

Hope this helps!
3 0
3 years ago
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Help plzz <br><br> h=8/7 (28)+92/4
Nostrana [21]

Answer:

h = 55

Step-by-step explanation:

Solve for  h  by simplifying both sides of the equation, then isolating the variable.

4 0
2 years ago
Read 2 more answers
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