The force of gravity between two objects is given by:
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation
In this problem, the mass of the object is
, while the Earth's mass is
. Their separation is
, therefore the gravitational force exerted on the object is
Answer:
total work is = 52450 J
Explanation:
given data
mass = 5000-lb
density = 10 lb/ft
height = 50 ft
solution
as we will treat here cable and ball are separate
and
here work need to lift cable is
w = (10Δy )(9.8 y ) j
and
now summing all segment of cable
so passing limit Δy to 0
so total work need
= 
= ![[49 y^2]^{50}_0](https://tex.z-dn.net/?f=%5B49%20y%5E2%5D%5E%7B50%7D_0)
= 2450J
so lifting 5000 lb wrcking 50 m required additional 5000 + 2450
so total work is = 52450 J
The prokaryotic cells are indeed smaller than the eularyotic cells.
Eukaruotic cell size -10-100um
Prokaryotic cell size - 1-10 um
Actually Welcome to the Concept of the Ohms Law,
According to the Ohms law,
V = I*R, where, V = Voltage, I = Current, R = resistance,
so here given as, V = 240 V, I = 32 A,
so we get as, R = 240/32
R = 7.5 ohms,
===> The resistant R is ==> 7.5 ohms.
Acceleration is defined as the rate of change for velocity. If the object is accelerating it is changing its velocity.
