Answer:
The length of the rod for the condition on the question to be met is 
Explanation:
The Diagram for this question is gotten from the first uploaded image
From the question we are told that
The mass of the rod is 
The mass of each small bodies is 
The moment of inertia of the three-body system with respect to the described axis is 
The length of the rod is L
Generally the moment of inertia of this three-body system with respect to the described axis can be mathematically represented as

Where
is the moment of inertia of the rod about the describe axis which is mathematically represented as

And
the moment of inertia of the two small bodies which (from the diagram can be assumed as two small spheres) can be mathematically represented as
![I_m = m * [\frac{L} {2} ]^2 = m* \frac{L^2}{4}](https://tex.z-dn.net/?f=I_m%20%20%3D%20%20%20m%20%2A%20%5B%5Cfrac%7BL%7D%20%7B2%7D%20%5D%5E2%20%3D%20%20m%2A%20%20%5Cfrac%7BL%5E2%7D%7B4%7D)
Thus 
Hence

=> ![I = [\frac{M}{12} + \frac{m}{2}] L^2](https://tex.z-dn.net/?f=I%20%20%3D%20%20%20%20%5B%5Cfrac%7BM%7D%7B12%7D%20%20%2B%20%5Cfrac%7Bm%7D%7B2%7D%5D%20L%5E2)
substituting vales we have
![0.929 = [\frac{3.41}{12} + \frac{0.249}{2}] L^2](https://tex.z-dn.net/?f=0.929%20%20%20%3D%20%20%20%20%5B%5Cfrac%7B3.41%7D%7B12%7D%20%20%2B%20%5Cfrac%7B0.249%7D%7B2%7D%5D%20L%5E2)


Answer:
electron λ = 12.5 nm
, bullet λ = 1.11 10⁻³³ m and golf ball λ = 4.7 10⁻³⁴ m
Explanation:
The Broglie wave duality principle states that all matter has wave and particle properties, it is expressed by the equation
p = h / λ
Where lam is called broglie wavelength
Let's use the definition of momentum
p = mv
Let's calculate the wavelengths
-Electron
mv = h /λ
λ = h / mv
λ = 6.63 10⁻³⁴ / (9.1 10⁻³¹ 5.81 10⁶)
λ = 1.25 10⁻¹⁰ m
λ = 12.5 nm
This is the X-ray region
-bullet
λ = 6.63 10⁻³⁴ / (1.90 10⁻³ 313)
λ = 1.11 10⁻³³ m
It is too small, only particle characteristics are observed
-Golf ball
λ = 6.63 10⁻³⁴ / (4.50 10⁻² 31.3)
λ = 4.7 10⁻³⁴ m
Too small, only particle characteristics are visible
Answer:
magnitude of vector is 276.19 kg m/s
Explanation:
The initial momentum is vector of magnitude
And driven in a coherent manner with initial vector.
same magnitude is momentum after the impact, but it is oriented perpendicularly to initial momentum vector.
So, you have 2 momentum vector of specified magnitude perpendicular to one another.
The contrast between such two vectors is a right angle triangle hypotenuse of 195.3 sides
magnitude of vector is 
Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.
Hope this helps
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