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zzz [600]
3 years ago
10

A 5000-lb wrecking ball hangs from a 50-ft cable of density 10 lb/ft attached to a crane. Calculate the work done if the crane l

ifts the ball from ground level to 50 ft in the air by drawing in the cable.
Physics
1 answer:
aniked [119]3 years ago
3 0

Answer:

total work is = 52450 J

Explanation:

given data

mass =  5000-lb

density = 10 lb/ft

height = 50 ft

solution

as we will treat here cable and ball are separate  

and

here work need to lift cable is

w = (10Δy )(9.8 y )  j

and

now summing all segment of cable

so passing limit Δy to 0

so total work need

= \int\limits^{10}_0 {98y} \, dy    

= [49 y^2]^{50}_0

= 2450J

so lifting 5000 lb wrcking 50 m  required additional 5000 + 2450

so total work is = 52450 J

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Answer:

The vehicle displacement is 9.90 feet.

Explanation:

Given that,

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An electrically neutral model airplane is flying in a horizontal circle on a 2.0-m guideline, which is nearly parallel to the gr
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Answer:

q=3.5*10^-4

Explanation:

<u>concept:</u>

The force acting on both charges is given by the coulomb law:

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the centripetal force is given by:

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