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svetlana [45]
3 years ago
12

Worth *20 points* Helpppp

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0
Yes. a linear graph does. Pass the vertical line test

Each value in the domain X,results in a unique range ,y, value
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En una estructura de concreto cuyo peso es de 8500 n se apoyo sobre un area de 25cm2,hallar la presion ejercida sobre su base
babymother [125]

Respuesta:

340 N/cm²

Explicación:

Paso 1: Información provista

Peso de la estructura (F): 8500 Newton

Area superficial (A): 25 cm²

Paso 2: Calcular la presión (P) ejercida por la estructura de concreto sobre su base

La presión es igual al cociente entre la fuerza ejercida y la superficie sobre la que se aplica.

P = F/A

P = 8500 N / 25 cm² = 340 N/cm²

5 0
3 years ago
If the initial concentration of a is 0.00540 m, what will be the concentration after 795 s?
zavuch27 [327]
<span>Feb 19, 2014 - The units of k tell you that this is a second order reaction. So, to solve this, you need to use the integrated rate law for a 2nd order reaction: 1/[A] = kt + 1/[A]o 1/[A] = 0.540/Ms (835 s) + 1/0.00640 1/[A] = 607 [A] = 1.65X10^-3 M.</span><span>
</span>
7 0
3 years ago
If a solution is saturated, which of these is true?
Fiesta28 [93]
If a solution is saturated, that means it already posses the maximum number of solutes thus have been dissolved in it, and thus the concentration cannot be increased.
8 0
3 years ago
Read 2 more answers
you are given a solution of lead nitrate. use any of the solution used in this experiment to form a white precipitate of lead ch
Vesnalui [34]

We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.

If a chlorine solution is used we will have the following reaction:

Pb(NO_{3)2}+2Cl^-\rightarrow PbCl_2+2NO^-_3

So, with a chlorine solution, we will have a white precipitate of lead chloride.

7 0
11 months ago
A 13.00 g sample of citric acid reacts with an excess of baking soda What is the theoretical yield of carbon dioxide
viva [34]

Answer:

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the <em>moles of H₃Cit </em>

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the <em>moles of CO₂ </em>

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the <em>mass of CO₂ </em>

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

4 0
3 years ago
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