Answer:
They have the same number of atoms. = YES
They have different masses. = YES
Explanation:
1 mol of beryllium
• 1 mol of salt
beryllium = Be = Atomic mass: 9.012182
salt = NaCl = Molar mass: 58.44 g/mol
1 mol of water
• 1 mol of hydrogen
water = H2O = Molar mass: 18.01528 g/mol
hydrogen = H = 1g/mole
Which statement is true about these substances?
They have exactly the same mass. = NO
They have different numbers of particles = NO
They have the same number of atoms. = YES
They have different masses. = YES
Avogadro constant means the number of units in one mole of any substance (defined as its molecular weight in grams) is equal to 6.02214076 ×
.
Answer:
Na+ is smaller than Na because, it has given away one electron because of which the electron shielding gets stronger due to more protons and less electrons. Whereas, Cl- is larger than Cl because it has gained an extra electron and so, the no.07/12/2010
Explanation:
The combinations of Strontium and chlorine that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.
1) The possible combinations are
- 4 strontium atoms and 8 chlorine
strontium atoms and
chlorine atoms
2) The combinations that are not possible are
- 20 strontium atoms and 60 chlorine atoms
- 130 billion strontium atoms and 195 billion chlorine
We have to work out the ratio of Strontium and chlorine in each of the given combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.
First case:
4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.
Second case:
20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.
Third case:
strontium atoms and
chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.
Fourth case:
130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.
Learn more: brainly.com/question/9743981
Answer : The value of
for this reaction is, 
Explanation :
The given chemical reaction is:

Now we have to calculate value of
.

![\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D%5Bn_%7BHCH_3CO_2%28g%29%7D%5Ctimes%20%5CDelta%20G%5E0_%7B%28HCH_3CO_2%28g%29%29%7D%5D-%5Bn_%7BCH_3OH%28g%29%7D%5Ctimes%20%5CDelta%20G%5E0_%7B%28CH_3OH%28g%29%29%7D%2Bn_%7BCO%28g%29%7D%5Ctimes%20%5CDelta%20G%5E0_%7B%28CO%28g%29%29%7D%5D)
where,
= Gibbs free energy of reaction = ?
n = number of moles
= -389.8 kJ/mol
= -161.96 kJ/mol
= -137.2 kJ/mol
Now put all the given values in this expression, we get:
![\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D%5B1mole%5Ctimes%20%28-389.8kJ%2Fmol%29%5D-%5B1mole%5Ctimes%20%28-163.2kJ%2Fmol%29%2B1mole%5Ctimes%20%28-137.2kJ%2Fmol%29%5D)

The relation between the equilibrium constant and standard Gibbs, free energy is:

where,
= standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol
R = gas constant = 8.314 J/L.atm
T = temperature = 
= equilibrium constant = ?
Now put all the given values in this expression, we get:


Thus, the value of
for this reaction is, 
There are two types of fluid in the body extracellular fluid and intracellular fluid (ECF and ICF), together they are account for total body water.
The Sodium (Na+) ion is at higher concentration in the extracellular fluid than in the intracellular fluid. The function of extracellular fluid is that it provide cells to watery environment so that they can easily live and perform their function.