When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).
How sulfate acts as electon acceptor and electron donor?
- Sulfate (SO₄²⁻) is used as the electron acceptor in sulfate reduction, which results in the production of hydrogen sulfide (H2S) as a metabolic byproduct.
- Many Gram negative bacteria identified in the -Proteobacteria use sulfate reduction, which is a rather energy-poor process.
- Gram-positive organisms connected to Desulfotomaculum or the archaeon Archaeoglobus also utilise it.
- Electron donors are needed for sulfate reduction, such as hydrogen gas or the carbon molecules lactate and pyruvate (organotrophic reducers) (lithotrophic reducers).
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This impurity is troubling from an economic standpoint because it lead to decrease in the yield of phosphorus
- Ferrophosphorus is a byproduct of phosphorus production in submerged-arc furnaces , by their reduction with carbon. It is formed from the iron oxide impurities.
- Iron impurities present in the calcium phosphate will be precipitated out as the iron phosphate which eventually will lead to the decrease in the yield of phosphorous during the production of phosphorous.
Thus we can conclude that Fe₂P causes decrease in yield
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Answer:
The answer to your question is 175 gallons
Explanation:
Data
60% antifreeze solution volume = ? = x
25% antifreeze solution volume = 25%
Final concentration 50%
Process
0.6x + 0.25(70) = 0.5(70 + x)
Simplification
0.6x + 17.5 = 35 + 0.5x
0.6x - 0.5x = 35 - 17.5
0.1x = 17.5
x = 17.5/0.1
Result
x = 175 gallons
Answer: 1
Explanation: Lithium has a single electron in the second principal energy level, and so we say that lithium has one valence electron.
Answer:
37.98 kPa.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂)</em>
<em></em>
P₁ = 101.3 kPa, V₁ = 1.5 L,
P₂ = ??? kPa, V₂ = 4.0 L.
- Applying in the above equation
<em>(P₁V₁) = (P₂V₂)</em>
<em></em>
<em>∴ P₂ = (P₁V₁)/V₂</em> = (101.3 kPa)(1.5 L)/(4.0 L) = <em>37.98 kPa.</em>
