Claim: The difference between two rational numbers always is a rational number
Proof: You have a/b - c/d with a,b,c,d being integers and b,d not equal to 0.
Then:
a/b - c/d ----> ad/bd - bc/bd -----> (ad - bc)/bd
Since ad, bc, and bd are integers since integers are closed under the operation of multiplication and ad-bc is an integer since integers are closed under the operation of subtraction, then (ad-bc)/bd is a rational number since it is in the form of 1 integer divided by another and the denominator is not eqaul to 0 since b and d were not equal to 0. Thus a/b - c/d is a rational number.
Answer:
C
Step-by-step explanation:
Because 0 lbs of sugar is required to make 0 muffins
I hope this is right
Answer:
+ 5y - 36
Step-by-step explanation:
(y-4)(y+9) = + 9y - 4y - 36
= + 5y - 36
hope this helps! :D
have a miraculous day!! <3
19.8
I really didn't understand your question, but if you could give me more details, that'd be great.
#I'm11
