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2 years ago

11

15x + 19 times 17x add 6 equal 180....(slove for x)

204%20%3D%20180" id="TexFormula1" title="15x + 19y \times 17 - 4 = 180" alt="15x + 19y \times 17 - 4 = 180" align="absmiddle" class="latex-formula">

1 answer:

Lady bird [3.3K]2 years ago

7 0

15x + 19y * 17 = 184
15x + 323y = 184
15x = 184 - 323y
x = 12.266 - 21.533y

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Write the equation of a quadratic function in standard form for the parabola that passes through the given points.

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5,7 given point its korrect now

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1 year ago

Property taxes are based on an assessed value of $132,000 and the tax rate is 8.5 mills. The property closes on Jun 14. On a bas

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Answer:

$132,000 X .0085 = $1,122 / 360 = $3.1166 X 164 = $511.13

One mill is one dollar per $1,000 dollars of assessed value.

In our case 8.5 mills equivalent to 0.0085.

So to get the assessed value for one day

we will get

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3 years ago

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3 years ago

Draw a line from each probability to the word or phrase that best describes the probability.

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Answer:

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2 years ago

Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat

riadik2000 [5.3K]

Answer:

a) $4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

b) $4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

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Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

Part b

$4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.4/2 =0.2 we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

5 0

3 years ago