Question

1250 randomly chosen individuals from a certain population are tested for the presence of the HIV virus, and 20 are found to be carriers of the virus. Based on this information, what is the estimate of P(V), the probability that a randomly chosen person from this population carries the HIV virus?

Answer 1

Answer:

0.016

Step-by-step explanation:

To find the probability we have to Divide the number of events by the total number of possible outcomes. This will result in the probability of the single event.

Therefore, the formula of probability is

$P(v) = \frac{no of events}{total possible outcomes}$

In the given case,

$P(v) = \frac{20}{1250}\\ P(v) = 0.016$

Which is our required answer.