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morpeh [17]
3 years ago
12

a mechanical engineer designs a robotic rm to be used in an assembly line. one portion of the arm is 5/12 yard long, and the len

gth of the second portion of the arm is 3/12 yard long.What wouldbe the length, in yards, of the robotic arm if the two portions of the arm were measured end to end?
Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

  8/12 yard or 2/3 yard

Step-by-step explanation:

The sum of the two lengths is ...

  5/12 yd + 3/12 yd = (5+3)/12 yd = 8/12 yd

This fraction can be reduced by removing a factor of 4 from numerator and denominator.

  8/12 yd = 2/3 yd

If the arm portions are end-to-end, the total length is 2/3 yard.

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in february, ayanna's electricity bill was ninety-two dollars. this was at least 3 dollars more than one-half her gas bill. writ
TEA [102]

Step-by-step explanation:

(92-3)x2=184 is the answer

4 0
3 years ago
The sum of two numbers is 53 and the difference is 19. What are the numbers?
Nostrana [21]
Let x be the smaller number.
So the bigger number is x+19 (Their difference is 19)
Their sum: 53
8 0
3 years ago
A parallelogram has vertices E(1, 4), F(5, 3), G(−3, 1), and H(1, 0). What are the coordinates of the midpoint of each diagonal?
kozerog [31]
Check the picture below.

now, the diagonals cut each other in two equal halves, thus, the midpoint of GF is the same coordinates as the midpoint for EH, so let's check what the midpoint for GF is then

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
G&({{ -3}}\quad ,&{{ 1}})\quad 
%  (c,d)
F&({{ 5}}\quad ,&{{ 3}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{5-3}{2}~~,~~\cfrac{5-1}{2}  \right)\implies \left( \cfrac{2}{2}~~,~~\cfrac{4}{2} \right)\implies (1,2)

5 0
3 years ago
1
antoniya [11.8K]

Answer:

4/5

Step-by-step explanation:

1, 2 , 3 and 4 are factors of 12

so 4 out of 5

4/5 is the probability of getting factor of 12

3 0
3 years ago
A car traveled a distance of 126 miles in 3 hours. Traveling at the same speed, what distance would this car travel in 7 hours?
Arte-miy333 [17]
First method: by the rule of three:
126 miles---------------------3 hours
x---------------------------------7 hours

x=(126 miles * 7 hours) / 3 hours=294 miles.

Answer: 294 miles.

Second method:
Speed=distance/ time           ⇒distance=speed x time

We calculate the speed of the car:
Speed=126 miles/3 hours= 42 miles/hour.

Data: 
Speed=42 miles/hour
time=7 hours

Distance=speed x time
Distance=(42 miles/hour)(7 hours)=294 miles

answer: 294 miles. 

3 0
3 years ago
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