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stiks02 [169]
3 years ago
15

A new baby elephant ate 2/3 bag of feed for breakfast. For lunch, the elephant ate 1/2 as much as he did for breakfast. How much

feed did the elephant eat for lunch?
Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

The answer is: \frac{1}{3} bag.

Step-by-step explanation:

A new baby elephant ate \frac{2}{3} bag of feed for breakfast.

For lunch, the elephant ate \frac{1}{2} as much as he did for breakfast.

Means he ate \frac{1}{2} \times\frac{2}{3} bag of feed for lunch.

It becomes \frac{1}{3} bag.

Lemur [1.5K]3 years ago
6 0
You would multiply the 2, so 2/3 times 1/2, so he had 2/6 simplified to 1/3
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Answer:

y=\frac{1}{4} x-3

Step-by-step explanation:

y=mx+b -- m = slope, b = y-int

5 0
3 years ago
Use the Leading Coefficient Test to determine the end behavior of the polynomial function . f(x) = 5x ^ 4 - 2x ^ 2
Alexxx [7]

Answer:

Step-by-step explanation:

hello :

f(x) = 5x ^ 4 - 2x ^ 2

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6 0
3 years ago
Consider U = {x|x is a real number}. A = {x|x ∈ U and x + 2 > 10} B = {x|x ∈ U and 2x > 10} Which statements are true? 5 ∉
-Dominant- [34]

x+2 > 10 solves to x > 8 after we subtract 2 from both sides

So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.


Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.


----------------


Summarizing everything, we can say...

5 is not in set A. True

5 is in set B. False

6 is in set A. False

6 is not in set B. False

8 is not in set A. True

8 is in set B. True

9 is in set A. True

9 is not in set B. False


5 0
3 years ago
Read 2 more answers
Sixty seven percent of the employees in a company have managerial positions, and 58 percent of the employees in the company have
Kazeer [188]

Answer: The proportion of employees who either have MBAs or are managers are 0.58.

Step-by-step explanation:

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Probability of managers having MBA degrees = 67%

So, using probability formulas, we get that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.67+0.58-0.67\\\\P(A\cup B)=0.58

Hence, the proportion of employees who either have MBAs or are managers are 0.58.

7 0
3 years ago
In problems below, (a) identify the independent variable and the dependent variable of each equation (use 't' for the independen
7nadin3 [17]

Step-by-step explanation:

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8 0
3 years ago
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