You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
-2, 1, 4, 7, 10, 13, 16, 19, 22
Answer:
y = 4
Step-by-step explanation:
distribute
10 + 2y = 18
minus 10 from both sides
2y = 8
divide by 2
y = 4
Answer:
-16.4, (commutative property)
Step-by-step explanation:
(add, because they are both negatives) -5.2+(-8.4)= -13.6
Then add the (-2.8): -13.6 + (-2.8) = -16.4
Thats your first equation!!!
do the same thing for the other one, and by the way it the same answer.
Its commutative prop because its just switching positions and its adding negatives.
Answer:
x=25
Step-by-step explanation:
60+70=130
180-130=50
50/2=25
