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mrs_skeptik [129]

3 years ago

12

6, 47, 49, 15, 43, 41, 7, 36 What is the third quartile

1 answer:

Tju [1.3M]3 years ago

3 0

6, 7, 15, 36, 41, 43, 47, 49

Q1- 9
Median- 38.5
Q3- 46
Sample Size- 8

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Rina8888 [55]

Answer:

The answer is A...

Step-by-step explanation:

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3 years ago

Read 2 more answers

45 minus 4.5. Show work

Dmitrij [34]

Let's do subtraction by first starting with the ones place and then the tenths place of the subtrahend.
45-4=41; 44, 43, 42, 41
41-.5= 40.5; 40.9, 40.8, 40.7, 40.6, 40.5
45-4.5=40.5
We can check by using addition.
40.5+4.5=
44+1=
45

3 0

3 years ago

How do you solve 39 equal to 1 3/10b

elena-s [515]

If 39 = (1 3/10)b, we could simplify this by writing 39 - (13/10)b.

Solve this for b by mult. both terms by (10/13):

(10*39)
----------- = (10/13)(13/10)b. Then b = 30 (answer)
13

5 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

3 years ago

Below is a plan of a vegetable plot.

Over [174]

10.2 all you have to do is add up all the sides... hope this helps!

3 0

3 years ago