B by making the solute particles smaller because it decrease the dissolving time.
like an example about tea and sugar when you stir the tea it allows the sugar to dissolve faster
Answer:
Option c → Tert-butanol
Explanation:
To solve this, you have to apply the concept of colligative property. In this case, freezing point depression.
The formula is:
ΔT = Kf . m . i
When we add particles of a certain solute, temperature of freezing of a solution will be lower thant the pure solvent.
i = Van't Hoff factor (ions particles that are dissolved in the solution)
At this case, the solute is nonvolatile, so i values 1.
ΔT = Difference between fussion T° of pure solvent - fussion T° of solution.
T° fussion paradichlorobenzene = 56 °C
T° fussion water = 0°
T° fussion tert-butanol = 25°
Water has the lowest fussion temperature and the paradichlorobenzene has the highest Kf. But the the terbutanol, has the highest Kf so this solvent will have the largest change in freezing point, when all the molalities are the same.
Answer:
you an see the answer at the pic
The answer would be C6H02
Answer : The molality of sodium chloride is, 1.79 m
Explanation :
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (sodium chloride) = 49 g
= Molar mass of solute (sodium chloride) = 58.5 g/mol
= Mass of solvent (water) = 469 g
Now put all the given values in above equation, we get:
Hence, the molality of sodium chloride is, 1.79 m