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Iteru [2.4K]
3 years ago
13

Which of the following contributes to nonpoint source pollution in water?

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
8 0
Garbage barges, cars, fish poop

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Calculate the molarity of 0.700 mol of na2s in 1.05 l of solution.
slamgirl [31]
Molarity is the amount of solute molecule (in moles) per 1L of solvent. In this case, the solute is 0.7mol Na2S and the solvent volume is 1.05L. Since the unit in this problem is already mol and L then you don't need to do any conversion of the units. The calculation would be:

molarity = mol of solute / (1L/ volume of solvent)
molarity = 0.7 mol/ (1L/ 1.05L)= 0.67M
6 0
3 years ago
Match the term with its description.
Ilia_Sergeevich [38]

pH(D) A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution

8 0
3 years ago
Read 2 more answers
given a density of 350 grams/cm3 and a mass of 25 grams. What is the volume using the equation involving density?​
Eduardwww [97]

0.07cm³

Explanation:

Given parameters:

Density of the body = 350g/cm³

Mass of the body = 25g

Unknown:

Volume of the body = ?

Solution:

Density is the amount of substance contained in a volume of body. It is expressed as:

    Density = \frac{mass}{volume}

Since the unknown is volume, we make it the subject of the expression;

   Volume = \frac{mass}{density}

 Volume = \frac{25}{350} = 0.07cm³

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

6 0
4 years ago
How do you get the electron configuration for an anion?
MissTica

Answer:

Anions electronic configuration is given by adding electrons.

4 0
3 years ago
Chamber 1 and Chamber 2 have equal volumes of 1.0L and are assumed to be rigid containers. The chambers are connected by a valve
vitfil [10]
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas  than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)

=> p1 = 2 p2

Which is easy to demonstrate using ideal gas equation:

p1 = nRT/V = 2.0 mol * RT / 1 liter

p2 = nRT/V = 1.0 mol * RT / 1 liter

=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2

2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.

So, the pressure in both chambers (which form one same vessel) is:

p = nRT/V = 3.0 mol * RT / 2liter

which compared to the initial pressure in chamber 1, p1, is:

p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1

So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.

You can also see how the pressure in chamber 2 changes:

p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
5 0
3 years ago
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