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rosijanka [135]
2 years ago
6

7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m

Chemistry
1 answer:
Anna [14]2 years ago
3 0

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ (n_{A}) = 1

Mole ratio of the base, NaOH (n_{B}) = 2

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH (M_{B}) = 0.505 M

Volume of the acid, H₂SO₄ (V_{A}) = 40 mL

Molarity of the acid, H₂SO₄ (M_{A}) = 0.505 M

<h3>Volume of the base, NaOH (V_{B}) =? </h3>

\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}

Cross multiply

0.505 * V_{B} = 20.2 * 2\\0.505 * V_{B} = 40.4

Divide both side by 0.505

V_{B} = \frac{40.4}{0.505}\\\\V_{B} = 80 mL

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

1000 mL = 1 dm^{3}\\\\Therefore,\\\\80 mL = \frac{80 mL * 1dm^{3}}{1000 mL}\\\\80 mL = 0.08dm^{3}

Therefore, the volume of NaOH required is 0.08 dm³

Learn more: brainly.com/question/19053582

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3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0
3 years ago
Does anyone know the answer to these?
Rashid [163]

Answer:

The answer to your question is below

Explanation:

Data

mass of CaCO₃ = 155 g

mass of HCl = 250 g

mass of CaCl₂ = 142 g

reactants = CaCO₃ + HCl

products = CaCl₂ + CO₂ + H₂O

1.- Balanced chemical reaction

             CaCO₃ + 2HCl   ⇒    CaCl₂ + CO₂ + H₂O

2.- Limiting reactant

molar mass of CaCO₃ = 40 + 12 + 48 = 100 g

molar mass of HCl = 2[1 + 35.5 ] = 73 g

theoretical proportion CaCO₃ /HCl = 100 / 73 = 1.37

experimental proportion CaCO₃ /HCl = 155 / 250 = 0.62

As the experimental proportion was lower than the theoretical proportion the limiting reactant is CaCO₃

3.-

Calculate the molar mass of CaCl₂

CaCl₂ = 40 + 71 = 111 g

          100 g of CaCO₃ ------------------ 111 g of CaCl₂

           155 g of CaCO₃ ----------------- x

               x = (155 x 111) / 100

               x = 17205 / 100

              x = 172.05 g of CaCl₂

4.- percent yield

Percent yield = 142 / 172.05 x 100 = 82.5 %

5.- Excess reactant

    100 g of CaCO₃  -------------------- 73 g of HCl

     155 g of caCO₃ ------------------- x

           x = (155 x 73)/100

           x = 133.15 g

Mass of HCl = 250 - 133.15

                    = 136.9 g

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Which of the following substances contain metallic bonds?
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PLEASE HELP 3.05 The atmosphere and you lab report
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Answer:

Objective(s):

to learn about the atmosphere and how we can help it

Hypothesis:

Carbon dioxide emissions will increase in the next century and global temperatures will increase.

Procedure:

Complete your hypothesis (above).

Identify the independent (test) variable and the dependent (outcome) variable: The emission is the independent variable. The temperature is dependent variable.

Practice using the computer model. Select each marker to see what it does. Here is a summary you can refer back to as you complete your experiment.

Carbon Dioxide Emissions Slider: You will use the arrows to change the amounts of carbon emissions.

Time Step Size: This will allow you to view the data every 5 years or every 10 years.

Start Over: Use this to reset the model if needed.

The current carbon emissions are 9.8 gigatons or 9.8 billion tons. Complete all three scenarios to find out what happens to the global temperature if these emissions stay the same, decrease, or increase over the next century. Follow the instructions in the Data section of this report.

Data:

For each scenario, record the carbon dioxide emission rate and the global temperature. The data for the years 1960–2010 are already filled out for you.

Scenario One: Carbon dioxide emissions stay the same

Set the carbon dioxide emissions rate to 9.8 gigatons.

Set the time step size to 10 years.

Select step forward until you have the data through the year 2110.

Record the data in the table below.

Year Carbon Emissions (gigatons) Temperature (Fahrenheit)

1960 4.2 57.2

1970 5.8 57

1980 6.2 57.4

1990 7.8 57.6

2000 8 58

2010 9.8 58

Maintain carbon dioxide emissions at 9.8 for the rest of scenario one.

2020 9.8 58.2

2030 9.8 58.6

2040 9.8 58.9

2050 9.8 59.1

2060 9.8 59.5

2070 9.8 59.7

2080 9.8 60

2090 9.8 60.1

2100 9.8 60.5

2110 9.8 60.7

Scenario Two: Carbon dioxide emissions decrease

Set the carbon dioxide emissions rate to 9.8 gigatons.

Set the time step size to 10 years.

Select the step forward button once.

Decrease the carbon dioxide emissions by 0.2 and press step forward.

Continue stepping forward once, decreasing the carbon emissions each time, until you reach 2110.

Record the data in the table below.

Year Carbon Emissions (gigatons) Temperature (Fahrenheit)

1960 4.2 57.2

1970 5.8 57

1980 6.2 57.4

1990 7.8 57.6

2000 8 58

2010 9.8 58

Decrease carbon dioxide emissions by 0.2 each step forward for the rest of scenario two.

2020 9.6 58.2

2030 9.4 58.6

2040 9.2 58.9

2050 9.0 59.1

2060 8.8 59.4

2070 8.6 59.6

2080 8.4 59.8

2090 8.2 60

2100 8.0 60.1

2110 7.8 60.3

Scenario Three: Carbon dioxide emissions increase

Set the carbon dioxide emissions rate to 9.8 gigatons.

Set the time step size to 10 years.

Select the step forward button once.

Increase the carbon dioxide emissions by 0.2 and press step forward.

Continue stepping forward once, increasing the carbon emissions each time, until you reach 2110.

Record the data in the table below.

Year Carbon Emissions (gigatons) Temperature (Fahrenheit)

1960 4.2 57.2

1970 5.8 57

1980 6.2 57.4

1990 7.8 57.6

2000 8 58

2010 9.8 58

Increase carbon dioxide emissions by 0.2 for each step forward for the rest of scenario three.

2020 10 58.2

2030 10.2 58.7

2040 10.4 59

2050 10.6 59.2

2060 10.8 59.6

2070 11 59.9

2080 11.2 60

2090 11.4 60.4

2100 11.6 60.8

2110 11.8 61

Conclusion:

Use your data to answer the following questions. Use complete sentences, and be as detailed as possible.

Summarize how the carbon emissions affected the atmospheric temperature in each of the three scenarios:

Scenario One: If the carbon emissions stay the same the temperature will still rise.

Scenario Two: If the carbon emissions go down then the temperatures will go up but slowly. 

Scenario Three: If the carbon emission goes up the temperatures will also go up faster.

Was your hypothesis supported by your results or not? Explain how you know. Yes, my hypothesis was correct. Because the data shows that as the carbon emissions increase the temperature will as well.

Explain the difference between the greenhouse effect and global warming. Global warming is a change in the earth that is causing it to heat up. The greenhouse effect is a natural change due to sunlight and the atmosphere.

Based on your knowledge of how the greenhouse effect works, why does the level of carbon dioxide affect the global temperature? because the more carbon dioxide the weaker the ozone layer gets cause that's the thing that keeps us safe from all the suns heat

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Explanation:

i got a 97 on it

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2 years ago
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