Answer:
mole fraction benzene = 0.62
mole fraction toluene = 0.38
Explanation:
Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:
<h2>p total = x₁ P⁰₁ + x₂ P⁰₂</h2>
where x1 and x2 for this solution denote the mole fractions of benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.
Solving the algebraic equation:
75 x₁ + 22 x₂ = 55
75 x₁ + 22 ( 1- x₁) = 55 (since x₁ + x₂ = 1)
75 x₁ + 22 - 22 x₁ = 55
53 x₁ = 33
x₁ = 0.62
x₂ = 1 - 0.62 = 0.38
The moles of disodium edta used is calculated using the below formula
moles =molarity x volume in liters
molarity=0.050m
volume in liters = 22/1000=0.022 L
moles is therefore= 0.022 x0.050 =1.1 x10^-3 moles of disodium edta
Answer:
A) , ,
A = 1.5×, A = 1.9×, A=1.5×
B) 4.469
Explanation:
From Arrhenius equation
where; K = Rate of constant
A = Pre exponetial factor
= Activation Energy
R = Universal constant
T = Temperature in Kelvin
Given parameters:
taking logarithm on both sides of the equation we have;
since we have the rate of two different temperature the equation can be derived as:
= 19846.04×7.544× = 1.497
= = 4.469
Bonds formed between atoms can be classified as ionic and covalent
Ionic bonds are formed between atoms that have a high difference in the electronegativity values.
In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds. If the atoms have very similar electronegativities, they form non-polar covalent bonds.
In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).
Answer:18 g
Explanation:
The molar mass of dextrose is obtained as shown. Then the formula for number of moles is applied as shown in the image. Number of moles= mass/molar mass= concentration × volume. The volume is measured in dm3 hence the denominator of 1000. By making mass of solute the subject of the formula, we obtain the mass of dextrose requited to prepare the desired concentration of solution in the desired volume.