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3 years ago

5

At Shannon's Beading Boutique, 6 out of the 20 beads on clearance are plastic. What percentage of beads on clearance are plastic

?
Write your answer using a percent sign (%).

2 answers:

yKpoI14uk [10]3 years ago

3 0

Answer:

30%

Step-by-step explanation:

(plastic beads)/(beads on clearance) = 6/20 = 30/100 = 30%

_____

A percentage is a representation of a fraction that has 100 as a denominator. The percent sign (%) is just a shorthand way to write "divided by 100" (/100). The word "percent" means "per hundred", or "divided by 100."

Here, the given fraction (6/20) can be multiplied by 5/5 to make it have a denominator of 100.

spayn [35]3 years ago

3 0

Answer:

30%

Step-by-step explanation:

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Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

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Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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