I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².
Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.
Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.
Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.
Add each length up and you get a perimeter of roughly 11.4
Answer:
Step-by-step explanation:
(a) The function ...
can be evaluated for x=-2√2 to get ...
The point (-2√2, 1) is on the graph of f(x).
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(b) Likewise, we can evaluate for x=2:
The point on the graph is (2, 0.8).
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(c) From part (a), we know that f(-2√2) = 1. Since the function is even, this means that f(2√2) = 1. The graph is a maximum at those points, so there are no other values for which f(x) = 1.
The points (±2√2, 1) are on the graph.
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(d) There are no values of x for which f(x) is undefined. The domain is all real numbers.
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(e) The only x-intercept is at the origin, (0, 0). The x-axis is a horizontal asymptote.
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(f) The only y-intercept is at the origin, (0, 0).
Answer:
0.2
Step-by-step explanation:
Given the data :
Day : Mon Tue Wed Thu Fri Sat Sun
# of sick days 22 11 16 17 21 28 25
The expected count of sick days taken on Saturday is obtained thus :
Expected count = (row total * column total) / overall total
Here, the table is just one way :
Hence, we use :
Observed value / total days
Hence,
Expected count on Saturday = sick days on Saturday / total sick days
Expected count on Saturday = 28 / (22+11+16+17+21+28+25)
Expected count on Saturday = 28 / 140
= 0.2
Answer:
ACB = 85
Step-by-step explanation:
First find x:
10+ x + 60 = 120 - x
x + 70 = 120 - x
Add x to both sides
2x + 70 = 120
subtract 70 from 120
2x = 50
Divide 2 from both sides
x = 25
10 + 25 + 60 = 95
Subtract 95 from 180
ACD = 85
Arc length = r θ =(3.9/2)*6.7 = 13.065 m.
Note: This arc angle is over 2 π , meaning that it will more than wrap around the circle.
