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anastassius [24]
3 years ago
13

What would happen when two or more waves are at the same place at the same time

Physics
1 answer:
velikii [3]3 years ago
5 0

Answer: They SUPERIMPOSE themselves.

Explanation:

When two or more waves are at the same place at the same time, They SUPERIMPOSE themselves. This follows a principle known as superposition, which states that when two more waves are traveling through the same medium at the same time,they pass through each other without being disturbed( that is, they superimpose). Therefore, in order to calculate the net displacement of the medium, the sum of the individual wave displacements is determined.

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LUCKY_DIMON [66]

One of the ways to help someone not to be influenced by media is:

  • Encourage independent thinking.
  • Let her know that she should make sure the information she is consuming is free from bias and is factual.

<h3>What is Media Influence?</h3>

This refers to the effects and reactions which the mass media has on the people who listen to them by shaping their views and by controlling the narrative.

With this in mind, we can note that if a person is overtly influenced by the media, then such a person lacks independent thinking and becomes emotional by what he watches on the television or reads from an online source.

This can be changed through the encouragement of independent thinking, and the need to check for factual information from the media news and also to focus more on studies.

Read more about media here:
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6 0
2 years ago
Does gravity increase or decrease with greater mass???
xz_007 [3.2K]

Answer:

Increase

As the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.

As the mass of either object increases, the force of gravitational attraction between them also increases.

Answered by none other than the <u><em>ONE</em></u> & <u><em>ONLY</em></u> <u><em>#QUEEN</em></u> herself aka<u><em> #DRIPPQUEENMO</em></u>

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6 0
3 years ago
The James Webb Space Telescope is positioned around 1.5 million kilometres from the Earth on the side facing away from the Sun.
Bad White [126]

The angular velocity depends on the length of the orbit and the orbital

speed of the telescope.

Response:

First question:

  • The angular velocity of the telescope is approximately <u>0.199 rad/s</u>

Second question:

  • The telescope should accelerates away by approximately F = <u>0.0005·m </u>

Third question:

  • <u>The pulling force between the Earth and the satellite</u>

<h3>What equations can be used to calculate the velocity and forces acting on the telescope?</h3>

The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun

The orbital velocity of the telescope = The Earth's orbital velocity

First question:

Angular \ velocity = \mathbf{\dfrac{Angle \ turned}{Time \ taken}}

The orbital velocity of the Earth = 29.8 km/s

The distance between the Earth and the Sun = 148.27 million km

The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77

Radius of the orbit, r = 149.77 million kilometer from the Sun

The length of the orbit of the James Webb telescope = 2 × π × r

Which gives;

r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers

Therefore;

Angular \ velocity = \dfrac{29.8}{941.03}\times 2 \times \pi \approx 0.199

  • The angular velocity of the telescope, ω ≈ <u>0.199 rad/s</u>

Second question:

Centrifugal force force, F_{\omega} = m·ω²·r

Which gives;

F_{\omega} = m \cdot \dfrac{28,500^2 \, m^2/s^2}{149.77 \times 10^9 \, m} \approx 0.0054233 \cdot m

Gravitational \ force,  F_G = \mathbf{G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}}

Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Mass of the Sun = 1.989 × 10³⁰ kg

Which gives;

F_G = 6.67408 \times 10^{-11} \times \dfrac{1.989 \times 10^{30} \times m}{149.77 \times 10^9} \approx   0.00592 \cdot m

Which gives;

F_{\omega} < F_G, therefore, the James Webb telescope has to accelerate away from the Sun

F = \mathbf{F_{\omega}} - \mathbf{F_G}

The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ <u>0.0005·m (away from the Sun)</u>

Third part:

Other forces include;

  • <u>The force of attraction between the Earth and the telescope </u>which can contribute to the the telescope having a stable orbit at the given speed.

Learn more about orbital motion here:

brainly.com/question/11069817

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Answer:

8.2N

Explanation:

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