Question

If its mass is 3.55×105 kg and the net braking force is 4.05×105 n , what is the airplane's acceleration?mastering physics

Answer 1

This problem illustrate an airplane which is decelerating, since it tells us about a braking force, this type of acceleration is opposite in direction or simply a "deceleration" of the aircraft. The given are mass m=3.55 x 10⁵ Kg. The net braking Force f=-4.05 x 10⁵ N or Newton. The formula for the force is equivalent to F=ma. therefore a=f/m or force divided by the mass. This braking force is acting in opposite direction therefore having a negative sign. The answer will be negative in sign reminding us that it is a form of "deceleration". The unit should be in m/s².

Answer 2

Answer:

$-1.14 m/s^2$

Explanation:

We can find the airplane's acceleration by using Newton's second law of motion, which states that:

$F=ma$

where

F is the net force on the airplane

m is the mass of the airplane

a is its acceleration

The problem says that the force is a braking force, so this means that the airplane is slowing down, therefore the acceleration must be negative and we must put a negative sign in front of the force. Re-arranging the equation, we can find the acceleration:

$a=\frac{F}{m}=\frac{-4.05\cdot 10^5 N}{3.55\cdot 10^5 kg}=-1.14 m/s^2$