Answer:
(a) 112.5 V/m
(b) 0.01494 T
Explanation:
velocity, v = 4.5 km/s = 4500 m/s
magnetic field, B = 2.5 x 10^-2 T
mass, m = 6.64 x 10^-26 kg
charge, q = 1.6 x 10^-19 C = 1.6 x 10^-19 C
(a) The force due to the magnetic field is balanced by the force due to the electric field
q E = B q v
E = B v = 2.5 x 10^-2 x 4500 = 112.5 V/m
(b) radius, r = 12.5 cm



B' = 0.01494 T
<span>longitudinal waves
Hope this helps!</span>
This is a big looking question for school and for 5 points.It seems to relate to superfluidity in helium III and helium IV and something called the "lambda" point. Though I can't do it justice yet and here, it looks as though i can find tis in "Heat and Thermodynamics", Mark W Zemansky ...If rho is the density of helium II, rhon the density of the normal part, and rhoz the density of the superfluid part rho=rhon+rhoz.At the lambda point, all the atoms are normal and rhon/rho = 1, whereas at absolute zero all the atoms are superfluid and rhon/rho=0.Best I can do with the info and point available ..ps, I think that both Bose and Einstein were nobel prize winners, and the word "Boson" is in honour of the, I believe, Indian physicist Bose. It is a very interesting question, and I can in no way do it justice here.
This property is called "Opacity".
The question is worded in a difficult way. A more easily understood wording of this question would be:
"<em>What is the name of the property of a material that prevents light passing through?"</em>
Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.