Answer:
so length of the fence is 250 feet
Explanation:
Given data
fencing (L) = 500 feet
enclose the garden = 3 sides
to find out
length of the fence
solution
we consider barn length x and width y
so we say x +2y = 500 ........1
we want to maximize length i.e xy = f
so we say
df/dx = ƛ × dL/dx
y = ƛ × 1
and
df/dy = ƛ × df/dy
x = ƛ × 2
from equation 1 we can say
2 ƛ + 2 ƛ = 500
so ƛ = 500/4 = 125
so that x = 2× 125 , y = 125
so x = 250 , y = 125
so length of the fence is 250 feet
Answer:
The risks and expense of manned deep water exploration must be balanced with the knowledge that will be gained.
Explanation:
Answer:
Explanation:
Intensity of sound = sound energy emitted by source / 4 π d² , where d is distance of the source .
A )
Intensity of sound at 1 m distance = 60 /4 π d²
d = 1 m
Intensity of sound at 1 m distance = 60 /(4 π 1²)
= 4.78 W m⁻² s⁻¹
B )
Intensity of sound at 1.5 m distance = 60 /4 π d²
d = 1.5 m
Intensity of sound at 1 m distance = 60 /(4 π 1.5²)
= 2.12 W m⁻² s⁻¹
C )
Intensity of sound due to 4 speakers at 1.5 m distance = 4 x 60 /4 π d²
d = 1.5 m
= 4 x 60 /(4 π 1.5²)
= 8.48 W m⁻² s⁻¹
D )
Intensity of sound due to .06 W speaker must be 10⁻¹² W s ⁻² . Let the distance be d .
.06 /4 π d² = 10⁻¹²
d² = .06 /4 π 10⁻¹²
d = 6.9 x 10⁴ m .
Answer:
Explanation:
30 N force is pulling total mass of 15 kg , so acceleration in the system of masses
= 30 / 15
= 2 m / s²
Let us now consider forces acting on 9 kg . 30 N is pulling it in forward direction . Tension T in the string attached to it is pulling it in reverse direction
so net force on it
30 - T
Applying Newton's law of motion on it
30 - T = mass x acceleration
30 - T = 9 x 2
30 - 18 = T
T = 12 N
Answer:
200 C
Explanation:
Let C1 and C2 be their charges. According to Coulomb's law
where k = 
is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force
Since their total charge is 200C:
or 
We can substitute the above equation
or 
So the larger charge is C = 200 C
