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telo118 [61]
3 years ago
12

A bunch of bananas cost $4, a pineapple cost $2 more than a bunch of bananas, and 4 apples cost one-half of a pineapple.1. Write

an equation that shows the cost of a pineapple (p) in terms of bananas (b). Use this equation to find the cost of a pineapple. 2. Write an equation that shows the cost of 4 apples (a) in terms of a pineapple (p). Use this equation to find the cost of 4 apples. 3. Write an equation that shows how much more a bunch of bananas cost compared to 4 apples where x is the unknown value. Then, solve the equation.
Mathematics
1 answer:
Bumek [7]3 years ago
7 0
1. b+2=p. 4+2=p. 6=p.
2. p/2=a. 6/2=a. 3=a
3. b-a=x. 4-3=x. 1=x
I'm in HS but this seems like it is the answer. If you need more explanation ask.
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Ryder Industries is considering a project that will produce cash inflows of $92,000 a year for five years. What is the internal
RSB [31]

Answer:

20.02%

Step-by-step explanation:

Formula : NVP = 0 =-P_0 + \frac{P_1}{(1+IRR)} + \frac{P_2}{(1+IRR)^2} + . . . +\frac{P_n}{(1+IRR)^n}

P_0 = 275000

n = 1,2,3,4,5

Substitute the values in the formula :

0 =-275000 + \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

275000 = \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

Solving for IRR using calculator

IRR = 20.02

Hence the internal rate of return if the initial cost of the project is $275,000 is 20.02%

4 0
3 years ago
Daniel has 15 yards of fabric to make a baby blanket
zubka84 [21]

Answer:

Than the baby blanket area is 15 yards. The length is 5 yards and the width is 3 yards.

3 0
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Which ratio expresses the scale used to create this drawing? The school has dimensions of 18 feet by 18 feet.
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2miles=20km
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3 0
3 years ago
Nationwide, it is estimated that 40% of service stations have gas tanks that leak to some extent. A new program in California is
fredd [130]

Answer:

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

Step-by-step explanation:

The sample proportion is p2= 7/27= 0.259

and q2= 0.74

The sample size = n= 27

The population proportion = p1= 0.4

q1= 0.6

We formulate the null and alternate hypotheses that the new program is effective

H0: p2> p1   vs  Ha: p2 ≤ p1

The test statistic is

z= p2- p1/√ p1q1/n

z= 0.259-0.4/ √0.4*0.6/27

z=  -0.141/0.09428

z= -1.496

The significance level ∝ is 0.05

The critical region for one tailed test is z ≤ ± 1.645

Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .

8 0
3 years ago
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