All categories

3 years ago

Paul used 1 gram of salt for a chemistry experiment. How many centigrams of salt did Paul use?

Mathematics

2 answers:

creativ13 [48]3 years ago

6 0

1 gram of salt is equal to 100 centigrams.

GrogVix [38]3 years ago

3 0

Answer: Paul used 100 centigrams of salt for a chemistry experiment.

Step-by-step explanation:

We know that 1 gram = 100 centigrams.

We are given that Paul used 1 gram of salt for a chemistry experiment.

But since 1 gram = 100 centigrams.

That means Paul used 100 centigrams of salt for a chemistry experiment.

Hence, the correct answer is Paul used 100 centigrams of salt for a chemistry experiment.

You might be interested in

A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.

Kobotan [32]

Answer:

The numbers are

$-2+3\sqrt{5}$ and $3\sqrt{5}$

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

$x=y-2$

$y=x+2$ ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

$4y+x^2=49$ ----> equation B

substitute equation A in equation B

$4(x+2)+x^2=49$

solve for x

$x^2+4x-41=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+4x-41=0$

$a=1\\b=4\\c=-41$

substitute in the formula

$x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}$

$x=\frac{-4\pm\sqrt{180}} {2}$

$x=\frac{-4\pm6\sqrt{5}} {2}$

$x=-2\pm3\sqrt{5}$

The positive real number is

$x=-2+3\sqrt{5}$

Find the value of y

$y=x+2$

$y=-2+3\sqrt{5}+2$

$y=3\sqrt{5}$

6 0

3 years ago

What is the length of DE? I need to find X. <br> A: 8 <br> B: 7<br> C: 5<br> D:6

erik [133]

The ratio of one triangle to the other (because they are similar, since the top angles are both 44 degrees and the two sides on the other sides of them are the same) is 12:8, or 3:2.

So therefore, we can say it's 9:6, so DE is 6.

3 0

2 years ago

Umm F soooo R me I need E help N with D this S

DiKsa [7]

12*12^3+2

12*1728+2

20736+2

20738

7 0

3 years ago

Read 2 more answers

Nicholas is currently in eighth grade and intends to attend a state college when he finishes high school. Nicholas’s parents cur

Juliette [100K]

Answer:

20,814.00

これがお役に立てば幸いです。また、良い一日をお過ごしください

7 0

2 years ago

Read 2 more answers

A national organization has been working with utilities throughout the nation to find sites for large wind machines that generat

kozerog [31]

Answer:

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.

Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

8 0

3 years ago