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3 years ago

What are the dimensions of a rectangle with an area of 72 square centimeters and a perimeter of 36 centimeters?

Mathematics

1 answer:

Masja [62]3 years ago

6 0

Answer:

length=12 cm, width=6 cm

Step-by-step explanation:

$lw = 72$

$w = \frac{72}{l}$

$2(l + w) = 36$

$l + w = 18$

$l + \frac{72}{l} = 18$

${l}^{2} + 72 = 18l$

${l}^{2} - 18l + 72 = 0$

$(l - 12)(l - 6) = 0$

$l = 12$

$w = 6$

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The volume of a box can be found by multiplying the length times width times height of a box (v=lwh). If the volume of a box is

Andrej [43]

Answer:

about 10.924 inches

Step-by-step explanation:

If all of the dimensions are equal, the box is a cube. Its side length is the cube root of the volume.

V = s³

s = ∛V = ∛1300 ≈ 10.913929 . . . . inches

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3 years ago

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I need help!! Don't just answer for the points!!

Kazeer [188]

Answer: Equation: E= 20H

Earning's after 15 hours: E= 20(15)

E = 300

Step-by-step explanation:

The equation would be E =20H. E means her total earnings. 20 is how much money she earns per hour. H is how many hours she tutors. If you put it all together, you get E = 20H.

To solve how much she would get for 15 hours, plug in 15 for H so E=20(15). 20 x 15 = 300. Therefore, she will get $300 after teaching for 15 hours.

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3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

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3 years ago

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PtichkaEL [24]

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3 years ago

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docker41 [41]

Answer:

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Step-by-step explanation:

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3 years ago

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