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BartSMP [9]
3 years ago
7

What are the dimensions of a rectangle with an area of 72 square centimeters and a perimeter of 36 centimeters?

Mathematics
1 answer:
Masja [62]3 years ago
6 0

Answer:

length=12 cm, width=6 cm

Step-by-step explanation:

lw = 72

w =  \frac{72}{l}

2(l + w) = 36

l + w = 18

l +  \frac{72}{l} = 18

{l}^{2} + 72 = 18l

{l}^{2} - 18l + 72 = 0

(l - 12)(l - 6) = 0

l = 12

w = 6

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
Select the statement that best justifies the conclusion based on the given information.
artcher [175]
Hope this helps but I think it is A.)addition property of equality.
6 0
4 years ago
Read 2 more answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
yan [13]

Answer:

  138.16 in²

Step-by-step explanation:

The surface area SA of the cone is the sum of the base area B and the lateral area LA. The lateral area is half the product of the circumference and the slant height. The radius is half the diameter, so is 4 inches.

  SA = B + LA

  = πr² + (1/2)(2πrh) . . . . where h is the slant height

  = (πr)(r +h)

Filling in the numbers, you have ...

  SA = (3.14)(4 in)(4 in + 7 in) = 3.14×(44 in²) = 138.16 in²

7 0
3 years ago
30 tens = ones<br> 30 tens = hundreds
Svetllana [295]

30 tens = 30 x 10 = 300

300 ones = 300 x 1 = 300

300 is your answer

30 tens = 30 x 10 = 300

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3 is your answer

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irina [24]
I think you need to show the tablle 
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