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3 years ago

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The slope of a line is 2, and the y-intercept is 0. What is the equation of the line written in slope-intercept form?

1 answer:

Orlov [11]3 years ago

7 0

The equation y=mx+b
Slope= m
y-intercept= b

y= 2x+0 so y=2x

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Please help me ASAP!Please

aleksandrvk [35]

Answer:

Option three

Step-by-step explanation:

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2 years ago

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A normal distribution has a standard deviation equal to 39. What is the mean of this normal distribution if the probability of s

Naily [24]

Answer:

The mean is $\mu = 131$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\sigma = 39$

What is the mean of this normal distribution if the probability of scoring above x = 209 is 0.0228?

This means that when X = 209, Z has a pvalue of 1-0.0228 = 0.9772. So when X = 209, Z = 2.

$Z = \frac{X - \mu}{\sigma}$

$2 = \frac{209 - \mu}{39}$

$209 - \mu = 2*39$

$\mu = 209 - 78$

$\mu = 131$

The mean is $\mu = 131$

7 0

2 years ago

When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of

makkiz [27]

Answer:

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So $A(t) \alpha \sin (\frac{t - \alpha }{k} )$

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

$A(t) = 2.2\sin \frac{(t)}{k} + 0.6$

at t = 2 sec volume of a is 0.6

So function reduce to

$A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6$

and t = 5 max value of volume is represent

so,

$\sin \frac{t - \alpha }{k} = 1$

$\frac{t - 2}{k} = \frac{\pi }{2}$ when t = 5

$\frac{6}{\pi } = k$

so the equation becomes

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

7 0

2 years ago

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3,−2), B(6, -2), C(6, 5) D

Vikki [24]

Answer:

Step-by-step explanation:

$Distance=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} \\$

A(3,-2) ; B(6,-2)

$AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\$

AB = 3 units

B(6,-2) ; C(6,5)

$BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\$

BC = 7 units

Area of rectangle = length * width

= AB * BC

= 3 * 7

= 21 square units

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3 years ago

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You are buying markers for the students in first grade. Each student will get 5 markers. There are 16 students in one class and

Masja [62]

52 markers that you will need to buy.

6 0

2 years ago

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