Question

What is the surface area of this triangular prism rounded to the nearest tenth? A) 48.6km2 B) 63.4 km2 C) 72.6 km2 D) 84.4 km2

Answer 1

Correct option B)$63.4km^2$ .

Step-by-step explanation:

We have the following figure attached as shown below.

Now, this triangular prism have 2 similar right angled surfaces and 3 rectangular surfaces , Let's calculate area for all of them:

2 similar right angled surfaces

We know that area of triangle = $\frac{1}{2} b(h)$

⇒ $area = \frac{1}{2} b(h)$

⇒ $area = \frac{1}{2} (3.6)(7.7)$

⇒ $area = 13.86km^{2}$

But there 2 such surfaces so , $area = 2(13.86) = 27.72km^2$

3 rectangular surfaces

Area of rectangle = $length(breadth)$

⇒ $area_1 = 3.6(1.8)$

⇒ $area_1 = 6.48km^2$

⇒ $area_2= 7.7(1.8)$

⇒ $area_2 = 13.86km^2$

⇒ $area_3 = 8.5(1.8)$

⇒ $area_2 = 15.3km^2$

Total area =$6.48 + 13.86 + 15.3 = 35.64km^2$

Adding area of 2 similar right angled surfaces & 3 rectangular surfaces:

$Area = 27.72+35.64 = 63.36km^2$ = $63.4km^2$

Correct option B)$63.4km^2$ .

Answer 2

Answer:

It is B.

Step-by-step explanation:

Trust me it's B