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2 years ago

Which of the following is a polynomial? I NEED HELP ASAP*******

Mathematics

1 answer:

nadezda [96]2 years ago

5 0

Answer:

7x⁷+2x⁻⁴+3 is a Polynomial

Step-by-step explanation:

I'm sorry I can't explain how I got the answer by hand. I graphed the Equation.

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Need help on simplifying this

Alex73 [517]

X-1/x is the answer you need for this

7 0

3 years ago

5/8y-12= -7<br> im stuck 9th grade math

Galina-37 [17]

Answer:

Step-by-step explanation:

$\frac{5}{8}y-12=-7 \\ \\ \frac{5}{8}y=5 \\ \\ y=8$

3 0

1 year ago

What is the substitution property of equality

malfutka [58]

The substitution property of equality, one of the eight properties of equality, states that if x = y, then x can be substituted in for y in any equation, and y can be substituted for x in any equation.

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2 years ago

If an object weighs 120 pounds on earth how much will it way on mars

butalik [34]

The surface gravity of Mars is 3.7 m/s². On Earth it is 9.8 m/s². 3.7/9.8 = 38%.

So 38% of 120 lbs is 45 pounds.

8 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$