Answer:
y=-7x+48 slope would be -7
Step-by-step explanation:
Used a Regression Calculator
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
71
Step-by-step explanation:
Area of fig 1 = 1 x b = 7 x 4 = 28
Area of fig 2 = l x b = (7-2) x 3 = 5 x 3 = 15
Area of fig 1 = 1 x b = 7 x 4 = 28 (same as ig 1)
Area of whole fig = fig 1 + fig 2 + fig 3 = 28+15+28 = 71
I hope im right !!
Answer:4.375
Step-by-step explanation:
Answer:
Sara earned a commission of <em>$2,300.</em>
Step-by-step explanation:
To find the answer we will first<em> divide 5 by 100</em> and we get <em>0.05</em>. Now <em>multiply $46,000 by 0.05 </em>and we get <em>$2,300</em>. Therefore, <em>$2,300 is our answer.</em>
