3 years ago

What is the multiplicative inverse of c/d? Explain how a number is related to its multiplicative inverse.

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

Answer:

$\frac{d}{c}$

Step-by-step explanation:

The multiplicative inverse of a number n is $\frac{1}{n}$

The product of the number and its multiplicative inverse = 1

n × $\frac{1}{n}$ = 1

Thus the multiplicative inverse of $\frac{c}{d}$ is

$\frac{1}{\frac{c}{d} }$ = $\frac{d}{c}$

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Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.

galben [10]

Answer:

The interval of increase of g(x) is $(-6,+\infty)$ .

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be $g(x) = 190 + 8 \cdot x^{3} + x^{4}$ , the first derivative of the function is:

$g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}$

$g'(x) = 4 \cdot x^{2}\cdot (6+x)$

The following condition must be met to define the interval of increase:

$4\cdot x^{2} \cdot (x+6) > 0$

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

$x + 6 > 0$